Get rid of the 'open in app' mobile prompt

We've determined that calls are working fine in mobile browsers these days and we no longer need it.
This commit is contained in:
Robin
2026-04-13 15:43:39 +02:00
parent 3b0dce33a2
commit 364fdb5e54
31 changed files with 8 additions and 331 deletions

View File

@@ -45,9 +45,6 @@ async function createCallAndInvite(
await creatorPage.getByTestId("home_go").click();
await expect(creatorPage.locator("video")).toBeVisible();
await creatorPage
.getByRole("button", { name: "Continue in browser" })
.click();
// join
await creatorPage.getByTestId("lobby_joinCall").click();

View File

@@ -23,8 +23,6 @@ test("@mobile Start a new call then leave and show the feedback screen", async (
// await page.pause();
await expect(page.locator("video")).toBeVisible();
await expect(page.getByTestId("lobby_joinCall")).toBeVisible();
await page.getByRole("button", { name: "Continue in browser" }).click();
// Join the call
await page.getByTestId("lobby_joinCall").click();
@@ -67,10 +65,6 @@ mobileTest(
const guestPage = await guestInviteeContext.newPage();
await guestPage.goto(inviteLink + "&controlledAudioDevices=true");
await guestPage
.getByRole("button", { name: "Continue in browser" })
.click();
await guestPage.getByTestId("joincall_displayName").fill("Invitee");
await expect(guestPage.getByTestId("joincall_joincall")).toBeVisible();
await guestPage.getByTestId("joincall_joincall").click();