ehofman fdd9bb1af6 Melchior FRANZ:
- check for isTied() and refcount has to be made *before* we go into
  recursion, so as to pertain subtrees of refcounted nodes, even if there
  are no refcounted/tied nodes *in* this tree
- return value inverted, because it's more logical to say
  removeChildren() == true --> everything removed;  false --> failed
- further cleanup
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Readme 14 MiB
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C++ 85.5%
C 13.1%
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