adds amount ferried between pairs as output value

This commit is contained in:
Andy Eschbacher
2017-05-18 20:33:14 -04:00
parent fe803d0b4b
commit 588e8b413f
2 changed files with 20 additions and 24 deletions

View File

@@ -7,7 +7,7 @@ CDB_OptimAssignments(source text,
dist_matrix_query text,
dist_rate numeric DEFAULT 0.15,
dist_threshold numeric DEFAULT null)
RETURNS table(drain_id bigint, source_id int, cost numeric) AS $$
RETURNS table(drain_id bigint, source_id int, cost numeric, amount numeric) AS $$
from crankshaft.optimization import Optim

View File

@@ -26,20 +26,13 @@ class Optim(object):
'solver': kwargs.get('solver', 'glpk')}
self._check_model_params()
# TODO: add source_fixed and source_free ids
# NOTE: this means that fixed sources will need to have their costs
# calculated separately
# TODO: drain_capacity will not be just reading the column - it will
# be reading the column and subtracting already-claimed values
# NOTE: after this, the rest of the algorithm _may_ be unchanged
# other than adding back the fixed sources to the table at the end of
# the calcuation
# database ids
self.ids = {
'drain': self.data_provider.get_column(drain_query,
'cartodb_id',
id_col='cartodb_id',
dtype=int),
'drain': self.data_provider.get_column(
drain_query,
'cartodb_id',
id_col='cartodb_id',
dtype=int),
'source_free': self.data_provider.get_column(
source_query,
'cartodb_id',
@@ -50,9 +43,7 @@ class Optim(object):
'cartodb_id',
dtype=int,
condition='drain_id is not null')}
plpy.notice('self.ids[drain]: {}'.format(self.ids['drain']))
plpy.notice('self.ids[source_free]: {}'.format(self.ids['source_free']))
plpy.notice('self.ids[source_fixed]: {}'.format(self.ids['source_fixed']))
# model data
self.model_data = {
'drain_capacity': self.data_provider.get_reduced_column(
@@ -72,7 +63,6 @@ class Optim(object):
self.data_provider.get_distance_matrix(dist_matrix_table,
self.ids['source_free'],
self.ids['drain'])}
plpy.notice(self.model_data)
self.model_data['cost'] = self.calc_cost()
self.n_sources = len(self.ids['source_free'])
self.n_drains = len(self.ids['drain'])
@@ -133,13 +123,19 @@ class Optim(object):
source_id_crosswalk[idx] = cid
# find non-zero entries
nonzeros = np.nonzero(assignments)
source_index, drain_index = nonzeros[0], nonzeros[1]
#
assigned_costs = [(drain_id_crosswalk[drain_index[idx]],
source_id_crosswalk[source_val],
self.model_data['cost'][drain_index[idx],
source_val])
source_index, drain_index = np.nonzero(assignments)
# returns:
# - drain_id
# - source_id
# - cost of that pairing
# - amount sent via that pairing
assigned_costs = [(
drain_id_crosswalk[drain_index[idx]],
source_id_crosswalk[source_val],
self.model_data['cost'][drain_index[idx], source_val],
round(self.model_data['source_amount'][source_val] *
assignments[source_val, drain_index[idx]], 6)
)
for idx, source_val in enumerate(source_index)]
return assigned_costs